Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. the osmotic pressures required for this process can be as high as 18.1 atm . what would the molar concentration of the tree sap have to be to achieve this pressure on a day when the temperature is 22 ∘c?

0.749 M

Explanation:

To solve this problem we use the formula

Where P is the osmotic pressure, M is the molar concentration, T is the temperature (in K) and R is the ideal gas constant 0.082 atm·L·mol⁻¹·K⁻¹

We put the data given by the problem and solve for M:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied