If 0.3041 g of a diprotic solid acid is neutralized by 35.45 ml of 0.0997 m naoh, calculate the malar mass of solid acid

Number of moles required to neutralize the solution=0.0354×0.0997

=0.0035mol

2 mol of NaOH required to neutralize 1 mol of diprotic acid.

So moles of acid 0.0035/2=0.0017

Number of moles of acid=Mass of diprotic acid/Molar mass of diprotic acid

0.0017 =0.3041/Molar mass of diprotic acid

Molar mass of diprotic acid=0.3041/0.0017

=178.8 g/mol

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

20 drops hope this