Oxalic acid is a diprotic acid. calculate the percent of oxalic acid (h2c2o4) in a solid given that a 0.7984-g sample of that solid required 37.98 ml of 0.2283 m naoh for neutralization.

The percent of oxalic acid in a solid is 48.87%.

Explanation:

Mass of the solid sample = 0.7984 g

Volume of NaOH solution = 37.98 mL = 0.03798 L

Concentration or molarity of the NaOH solution = 0.2283 M

Moles of NaOH :

According to reaction,  2 moles of sodium hydroxide reacts with 1 mole of oxalic acid .

Then 0.0086708 moles of sodium hydroxide will react with:

of oxalic acid.

Mass of oxalic acid neutralized = 0.0043354 moles × 90 g/mol =0.390186 g

Percentage of oxalic acid in solid sample :

The percent of oxalic acid in a solid is 48.87%.

2b2t

explanation:

2b2t