Alaboratory experiment requires 2.25 l of a 1.0 m solution of phosphoric acid (h3po4), but the only available h3po4 is a 9.0 m stock solution. how could you prepare the solution needed for the lab experiment? show all the work used to find your answer.

The solution needed is prepared  as below

by use of the   M1V1 =M2 V2  formula  where
M1 = 2.25 L
v2 = 1.0M
M2 = 9.0 M
V2 =? l

make V2  the subject of the formula  V2 =M1V1/M2

= 2.25 L x  1.0M/9.0 M  = 0. 25 L

therefore  the solution  need  0.25 L  of   9.0M H3PO4   and  dilute it a final volume  of 2.25 l 

We know that, M1V1   =   M2V2
                        (Initial)      (Final)

Given: M1 = 9.0 M
            M2 = 1.0 M
            V2 = 2.25 L

Therefore we have, 9.0 x V1 = 1.0 x 2.25
                                         V1 = 0.25 L

Thus, 0.25 L of stock solution (9.0 M), when diluted till 2.25 L, the resultant solution will have concentration 1.0 M.

Sorry i dont understand the question can you rephase it?