Modify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the shown locations. use vector adt's erase() and insert() only, and remember that the first argument of those functions is special, involving an iterator and not just an integer. sample output of below program:

Following are the code to this question:

#include <iostream>//defining header file

#include <vector>//defining header file

using namespace std;

void PrintVectors(vector<int> numsList)//defining a method PrintVectors that accept an array

{

   int j;//defining integer variable

   for (j = 0; j < numsList.size(); ++j)//defining for loop for print array value  

   {

       cout << numsList.at(j) << " ";//print array

   }

   cout << endl;

}

int main()//defining main method  

{

   vector<int> numsList;//defining array numsList

   numsList.push_back(101);//use push_back method to insert value in array

   numsList.push_back(200);//use push_back method to insert value in array

   numsList.push_back(103);//use push_back method to insert value in array

   numsList.erase(numsList.begin()+1);//use erase method to remove value from array

   numsList.insert(numsList.begin(), 100);//use insert method to add value in array

   numsList.insert(numsList.begin()+2, 102);//use insert method to add value in array

   PrintVectors(numsList);//use PrintVectors method print array value

   return 0;

}

Output:

100 101 102 103  

Explanation:

In the above-given code, inside the main method an integer array "numList" is defined, that use insert method to insert value and use the erase method to remove value from the array and at the last "PrintVectors" method is called that accepts a "numList" in its parameter. In the "PrintVectors" method, a for loop is declared, that prints the array values.

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i believe your answer would be c.. : )