Consider the cross Aa BB Cc dd X Aa bb cc Dd. Assume that the four allelic pairs assort independently. (a) How many different types of gametes can the parent with the genotype Aa BB Cc dd produce?

The parent with the genotype Aa BB Cc dd can produce 4 different types of gametes.

Explanation:

The law of independent assortment states that the alleles for a trait separate when gametes are formed.

In the parent genotype Aa BB Cc dd, the allelic pairs with variation present are Aa and Cc. Therefore, the source of variation in the possible combinations  during meiosis, largely arises from these 2 allelic pairs.

Independently assorting these pairs, we have ; A, a, B, B, C, c, d, d

The possible combinations therefore are:

1. a host loses nutrients to a parasite

2. a parasite only benefits when the host is alive (cause if the host dies the parasite dies with it )

3. producers to consumers

4. the tapeworm is a parasite

5. they convert energy from the sun (photosynthesis)

6. sunflower-robin (i think im 80% sure)

7. producer

8. consumer

9. prey

10. fresh water snails ( cause the green algea is the producer and the snails are the primary consumers and the small fish consumer so is the big fish)

the unequal cytoplasmic division that  results  in  one egg  and three polar bodies ensures that a fertilized  egg has  ample nutrients  forits journey  to  the uterus.