29 Halla dos números consecutivos tales que, añadiendo al mayor la mitad del menor, el resultado excede en 13 unidades a la suma
de la quinta parte del menor con la onceava parte del mayor.

Los dos números son:

10 y 11

Explanation:

a = primer número (menor)

a+1 = consecutivo   (mayor)

entonces:

a+1 + a/2 = a/5 + (a+1)/11 + 13

a + a/2 - a/5 - (a+1)/11 = 13-1

110a/110 + 55a/110 - 22a/110 - 10(a+1)/110 = 1320/110

110a + 55a - 22a - 10(a+1) = 1320

165a - 22a - 10*a - 10*1 = 1320

143a - 10a - 10 = 1320

133a = 1320 + 10

133a = 1330

a = 1330/133

a = 10

a + 1 = 11

Comprobación:

11 + 10/2 = 10/5 + 11/11 + 13

11 + 5 = 2 + 1 + 13 = 16

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the answer is d

explanation:

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