A 0. 14-kg baseball is dropped from rest from a height of 2. 0 m above the ground. What is the magnitude of its momentum just before it hits the ground if we neglect air resistance?.

0.8764kgm/s

Explanation:

Finding the velocity(v) before it hits the ground , where g is 9.8m/s²

v²= u² + 2gh

v² = 0 + 2× 9.8 × 2

v² = 40

v = √39.2

=6.26m/s

momentum= mass × velocity

= 0.14 × 6.26

= 0.8764kgm/s

the answer is:

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hope it !

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