SAT
SAT, 11.11.2021 03:30, kat2788

Manuela solved the equation 3βˆ’2|0. 5x+1. 5|=2 for one solution. Her work is shown below. 3βˆ’2|0. 5x+1. 5|=2 βˆ’2|0. 5x+1. 5|=βˆ’1 |0. 5x+1. 5|=0. 5 0. 5x+1. 5=0. 5 0. 5x=βˆ’1 x=βˆ’2 what is the other solution to the equation? x=βˆ’6 x=βˆ’4 x=2 x=4.

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Manuela solved the equation 3βˆ’2|0. 5x+1. 5|=2 for one solution. Her work is shown below. 3βˆ’2|0. 5x+1...

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