If A and B are positive integer and A∆B =A(A+2B) , what is the value of 2∆(4∆(1∆B)} ?

If A ∆ B = A × (A + 2B) = A² + 2AB, then

• 1 ∆ B = 1 + 2B

• 4 ∆ (1 ∆ B) = 4 ∆ (1 + 2B) = 24 + 16B

• 2 ∆ (4 ∆ (1 ∆ B)) = 2 ∆ (24 + 16B) = 100 + 64B

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