80% male students are majoring in engineering. 47% of students are male. What is the probability a student chosen at random will be a male majoring in engineering.

0.376

Explanation:

Probability of male student  [ P (MS) ] = 47% = 0.47

Probability male students majoring in Engineering [ P (E / MS) ]  = 80% = 0.80  

Probability that a student chosen is male & majoring in engineering  

= P ( E ∩ MS )

As per conditional probability rule :

P (E / MS)  = P ( E ∩ MS )

                       P ( MS )

So, P ( E ∩ MS )  = P (E / MS) x  P ( MS )

= 0.80 x 0.47

= 0.376

0.376

Explanation:

Percentage of male students in the class ; 47% = 47/100 = 0.47

percentage of male students majoring in engineering= 80% = 80/100 = 0.8

probability of randomly choosing a male majoring in engineering in the class;

P= 0.47 x 0.8 = 0.376

what am i trying to do? solve?