If f(x)=(x+3)³+4
let g(x)=f(x+1)-2
find when g(x)=12

Explanation:

g(x) = f(x + 1) - 2

g(x) = (x + 1 + 3)^3 -2

g(x) = (x + 4)^3 - 2

Now what are we supposed to do with this? I'm guessing we are to find what value of x will make g(x) = 12. If I'm wrong, leave a note in the form of a comment.

g(x) = 12

(x + 4)^3 - 2 = 12                 Add 2 to both sides.

(x + 4)^3 = 14                      Take the cube root of both sides.

x + 4 = cubrt(14)

x + 4 = 2.4101                      Subtract 4

x = 2.4101 - 4

x = -1.5899