If you weigh 670 n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 25.0 km ? take the mass of the sun to be m s = 1.99×1030 kg , the gravitational constant to be g = 6.67×10−11 n⋅ m 2 /k g 2 , and the acceleration due to gravity at the earth's surface to be g = 9.810 m/ s 2 .

The weight of an object at the surface of a planet is given by:

where m is the mass and g is the gravitational acceleration, given by

where G is the gravitational constant, M is the planet's mass, and r the radius of the planet.

At Earth's surface, . Since we know the weight of the person at Earth's surface, F=670 N, we can find his mass:


Now we have to calculate the value of g at the surface of the neutron star. The mass of the neutron star is 25 times the Sun's mass:


While its radius is:


Therefore, the value of g at the neutron star surface is


Therefore, the weight of the person at the surface of the neutron star would be

Year  1936,  lehman predicted that the earths 'inner core' is solid. she observed that the seismic signals during her study were bent and did not pass through instead bouncing back. later it was confirmed that the earth's inner core was solid made up of nickel-iron and had a molten outer core.

Bis the answerhope it !