Physics, 21.07.2019 11:30, smiley29162

If a hydrogen atom in the ground state absorbs a photon of energy 12.09 ev, to which state will the electron make a transition?

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The energy levels of the hydrogen atom are given by
$E_n = -13.6 \frac{1}{n^2} [eV]$ (1)
where n is the level number. Therefore, the ground state has energy of
$E_1 = -13.6 \frac{1}{1^2} eV = -13.6 eV$

If the atom absorbs a photon of energy E=12.09 eV

, the final energy of the hydrogen atom is
E_f = E_1 + E = -13.6 eV + 12.09 eV =-1.51 eV

And we can use eq.(1) to find the corresponding level number:
$n= \sqrt{ \frac{-13.6 eV}{E_f} } = \sqrt{ \frac{-13.6 eV}{-1.51 eV}}= \sqrt{9}=3$
So, the electron made a transition to the n=3 level.

answered: Guest

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answered: Guest

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