Asound from a source has an intensity of 270 db when it is 1 m from the source. what is the intensity of the sound when it is 3 m from the source? 30 db 90 db 810 db 2430 db

Remember that sound intensity decreases in inverse proportion to the distance squared. So, to solve this we are going to use the inverse square formula: 
where
is the intensity at distance 2
is the intensity at distance 1
is distance 2
is distance 1

We can infer for our problem that , , and . Lets replace those values in our formula to find :




dB

We can conclude that the intensity of the sound when is 3 m from the source is 30 dB.

Ibelieve the answer you're looking for is

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.