The drive chain in a bicycle is applying a torque of 0.850 nm to the wheel of the bicycle. treat the wheel as a hoop with a mass of 0.750 kg and a radius of 33.0 cm. what is the angular acceleration of the wheel

The equivalent of Newton's second law for rotational objects is given by:

where
is the net torque acting on the object
is its moment of inertia
is its angular acceleration

For a hoop rotating around its perpendicular axis, the moment of inertia is

where m is the mass and r the radius. By using the data of the wheel, m=0.750 kg and r=33.0 cm=0.33 m, we find


and since the torque is , the angular acceleration of the wheel is

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Lexy is correct because angle r is between the incident wave,  n  = 0, and a diffracted wave.