How much heat is absorbed by a 74g iron skillet when its temperature rises from 7oc to 28oc?

The specific heat of iron (assuming the skillet is pure iron) is 0.45 J/g-C. Then we use the equation q = mc(dT) to determine the total heat absorbed. This gives:
q = (74 g)(0.45 J/g-C)(28 - 7 C) = (74)(0.45)(21) = 699.3 J