How much time does it take to travel from the position of 25m to a position of 100m at an average speed of 15m/s?

100-25=75
speed=distance/time so time=distance/speed
75/15 =5 seconds

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.

This  kingdom  is  made  up of species that  do  not really easily fit into other kingdoms such as the plant, animal,and  fungi  kingdom. some protists, such as the paramecium  and  amoeba, feed  on  other  organisms  while others such as algae are able to  make their own food  through the process of photosynthesis.