Two electrons are separated by a distance of 3.00 x 10^-6 meter. what are the magnitude and direction of the electrostatic forces each exerts on the other?

The magnitude and direction of the electrostatic forces each exerts on the other are in opposite direction.

The given parameters:

Distance between the two electrons, r = 3 x 10⁻⁶ mCharge of each electron, q = 1.6 x 10⁻¹⁹ C.

The magnitude and direction of the electrostatic forces each exerts on the other is calculated as follows;

Thus, the magnitude and direction of the electrostatic forces each exerts on the other are in opposite direction.

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The electrostatic force between two charges q1 and q2 is given by

where 
is the Coulomb's constant
is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 


By substituting these values, we find the intensity of the force between the two electrons:


This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.

Multiply the 3 dimensions, assuming it is a rectangular cuboid, to get the volume in cm³ divide mass by volume to get density in g/cm³

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