Physics, 27.07.2019 15:30, logan12345677885675

How much work is required to lift a 2000-kg satellite from the surface of 7x10^6 the earth to an altitude of m?

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The correct text of the problem is: "How much work is required to lift a 2000-kg satellite from the surface of the earth to an altitude of 7x10^6 m?"

Solution:The work needed to lift the satellite from the surface of Earth to an altitude h is equal to the increase in gravitational potential energy of the satellite moving from the surface of Earth to altitude h. This variation of gravitational potential energy is given by:
$\Delta U=mg\Delta h$
where m is the mass of the satellite, g is the gravitational acceleration and dh is the variation of altitude. The work is equal to this variation of energy:
$W=\Delta U$
The mass of the satellite is m=2000 kg while the variation of altitude is
$h=7 \cdot 10^6 m$
so we can plug these data into the equation to calculate the variation of gravitational potential energy, which is equal to the work done on the satellite: $W=\Delta U=(2000 kg)(9.81 m/s^2)(7\cdot 10^6 m)=1.4\cdot 10^{11} J$

answered: Guest

sleep paralysis is a parasomnia, events associated with sleep.

sleep paralysis happens when you are in the middle of waking up or falling asleep. it is the feeling of being conscious but unable to move. it definitely involves hallucinations.

i had a friend that had sleep paralysis and he told me a story one time where he was laying in bed and he couldn't move his body no matter how hard he tried and there was someone standing in the corner of his room coming towards him. he couldn't move and you can't "wake up" because you are already conscious. sometimes sleep paralysis can be triggered by frequent waking up during the night based off of multiple trips to the bathroom, or if you had ever been abused, sleep paralysis can start happening from things like that.

answered: Guest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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How much work is required to lift a 2000-kg satellite from the surface of 7x10^6 the earth to an alt...