Jasper and gemma are going to play on a teeter totter. gemma gets on first. when jasper gets on, gemma moves into the air, but she does not move to the top. which statement could correctly explain the forces acting on the teeter totter? the forces are balanced because jasper weighs the same as gemma.  the forces are unbalanced because jasper weighs the same as gemma.  the forces are balanced because jasper weighs more than gemma.  the forces are unbalanced because jasper weighs more than gemma. 

The forces are unbalanced because Jasper weighs more than Gemma
The side that Gemma is on will only move upwards if the force exerted on the other side is greater than the force exerted by Gemma. In this case, force is referring to the weight of the children. Therefore, in order for Gemma to go upwards, Jasper must weigh more than her.

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s