During the construction of an office building, a hammer is accidentally dropped from a height of 784 ft. the distance (in feet) the hammer falls in t sec is s = 16t2. what is the hammer's velocity when it strikes the ground?

The hammer's velocity when it strikes the ground is 128 ft/s.

Explanation:

Given that,

The distance (in feet) the hammer falls in t sec is given by the relation as :

The hammer is accidentally dropped from a height of 784 ft. We need to find the hammer's velocity when it strikes the ground. We know that the velocity of an object is equal to :

When the hammer strikes ground, s = 256 ft

So,

So, the velocity of the hammer when it strikes the ground is given by :

So, the hammer's velocity when it strikes the ground is 128 ft/s. Hence, this is the required solution.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y