Ametal cube, 2.00cm on each side, has a density of 6600 kg/m3. find its apparent weight when it is totally submerged in water.

 0.439488 N

Explanation:

The apparent weight of the metal is computed as

apparent weight = weight - weight of the displaced fluid 

To compute the weight of the metal, we use the following formula:



where 





Note that the volume is unknown but we can compute this because the metal is a cube with edge = 2 cm = 0.02 m. So, the volume of the metal is given by



Thus, the weight of the metal is computed as



Next, we compute the displaced weight or buoyancy, which has the following formula



where



Note that the displaced volume is equal to the volume of the submerged metal. Since the metal has a volume of , the displaced volume is . 

Thus, the weight of the displaced fluid is calculated as 



Therefore,

apparent weight of the metal
= weight of the metal - weight of the displaced fluid 
= 0.517968 N - 0.07848 N
apparent weight of the metal = 0.439488 N

Nucleus for question ome