What is the net force in the x-direction? 30 n 34 n 55 n 65 n

Answer

34 N

Explanation.

I think the question is not complete.. It should be "A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"

We should find the horizontal component of the force 65 N.

Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.

cosФ = adjacent/hypotenuse

let x be the net required (the component of 65N)

cos 58 = x/65

x = 65 × cos 58

= 34.44 N

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