When a 57-gram piece of aluminum at 100oc is placed in water, it loses 735 calories of heat while cooling to 30oc. calculate the specific heat capacity of the aluminum. 30

cal=0.184 cal g−^1∘c−^1

the specific heat of aluminum tells you the amount of heat needed or released when the temperature of 1 gram of aluminum changes by 1  ∘c.

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true, as the earth rotates the sun hits the surface of the planet; causing the day and night cycle.