What is the momentum of the system after the collision?

0.0 kg • m/s
0.2 kg • m/s
0.3 kg • m/s
0.4 kg • m/s

 The momentum of the system after the collision is 0.2 kg m/s.

Explanation:

According to the conservation of momentum, the total momentum of the system before the collision is same the total momentum of the system after the collision in an isolated system.

Here, m_{1},m_{2} are the first and second object, v_{1},v_{2} are the initial velocities of the first and second objects and u_{1},u_{2} are the final velocities of the first and the second objects.

Use the formula of the conservation of the momentum.

Put m_{1}=0.6 kg, m_{2}=0.5 kg, v_{1}=0.5 m/s and v_{2}=-0.2 m/s.

= 0.2 kg m/s" alt="m_{1}u_{1}+m_{2}u_{2}" />= 0.2 kg m/s" />

Therefore, the momentum of the system after the collision is 0.2 kg m/s.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow