Aman stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. what is the velocity of the man according to a stationary observer?

With respect to stationary observer the velocity of man is 0.3 m/s towards South

Explanation:

As we know that here man is standing still on the moving walkway

so here we can say that velocity of man with respect to walkway is zero

now as per relative velocity concept we know

here we know

= velocity of man with respect to stationary observer

= velocity of walkway

now from above equation we have

now plug in all values in it

towards South

a) are muscles that have bands.

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  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz