At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 790.0 k?

C4H8(g) --> 2C2h4(g)

At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 790.0 K?"

To solve the exercise, we can use Arrhenius equation:

where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using  and , and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have

And so

And using , we find K2:

answer is slate

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