How much heat is absorbed by a 34g iron skillet when its temperature rises from 11oc to 26oc?

Answer is: 229,5 J of heat is absorbed.
m(mass of iron - Fe) = 34 g.
ΔT( change in temperature) = 26°C - 11°C = 15°C.
cp( specific heat capacity for iron) = 0,450 J/g·°C.
Q( heat absorbed) = m(Fe) · ΔT · cp.
Q = 34 g · 15°C · 0,450 J/g·°C.
Q = 229,5 J = 0,2295 kJ.

The correct answer should be b let me know if i’m wrong