Abullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. if it enters with a speed of 450 m/s and emerges with a speed of 220 m/s, what is the bullet's acceleration as it passes through the board?

The acceleration of a bullet that is fired through a board of 14.0 cm thick, with an initial and final speed of 450 m/s and 220 m/s, respectively, is -5.50x10⁵ m/s².  

The acceleration of the bullet can be calculated with the following equation:

  (1)

Where:

: is the final speed = 220 m/s

: is the initial speed = 450 m/s

a: is the acceleration =?

d: is the distance = 14.0 cm = 0.14 m

Hence, by solving equation (1) for a, we have:

The minus sign is because the bullet decelerates as it passes through the board.  

Therefore, the bullet's acceleration as it passes through the board is -5.50x10⁵ m/s².

To learn more about negative acceleration, go here: link

I hope it helps you!  

Explanation:

Here we know

initial speed will be

final speed is

total distance moved through it is given as

now we will use kinematics to find the acceleration

(75°f − 32) × 5/9 = 23.889°c

f is prop to m1xm2 double m1 double force