A0.20-f capacitor is desired. what area must the plates have if they are to be separated by a 3.2-mm air gap?

We have that the Area is mathematically given as

A=7.23e7 m^2

Generally the equation for the Capacitor   is mathematically given as

C= ( ε0x A) / d

where

d = 3.2-mm

d= 3.2 e-3 m

Therefore

A = C *dε0

A= 0.20 F * 3.2 E-3 m /  8.85 x 10^-12 [F/m]

A=7.23e7 m^2

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i think the answer would be reserve.