The pressure on a gas at −62◦c is doubled, but its volume is held constant. what will the final temperature be in degrees celsius? answer in units of ◦c.

We know that the relation between pressure, volume and temperature is constant for ideal gases, so then
   P1*V1/T1 = P2*V2/T2

   As the volume is held constant, we will have:
   P1/T1 = P2/T2

   As the pressure is doubled and the temperature in kelvins is 211.15 K, then:
   P1/211.15 = 2*P1/T2
 T2 = 2*211.15 = 422.3 K
  T2 = 422.3 - 273.15 = 149.15
   So the final temperature reaches 149.15 ÂşC