If a football player positioned on the scrimmage line runs straight downfield for 26 yards and then cuts to his left for 6.0 yards to receive a pass, what is the football player's total displacement from the scrimmage line? (use trigonometry to answer, but remember to draw a diagram to your understanding.) give both the magnitude and the angle in your answer.

In the problem you are given what basically amounts to two sides (the legs) of a right triangle.
 We are trying to find the hypotenuse of the triangle (which is the displacement).
 Using the Pythagorean Theorem 
 a^2+b^2=c^2 
 we will plug in 26 and 6 for a and b, and then solve for c yielding an answer of 26.6833 yards.
 To find the angle from the direction he ran forward, we can use a trigonometric function.
 I will use the tangent function since we are given the adjacent and opposite sides (tanθ=(opp/.adj.) 
 tanθ=(6/26).
 This yields a theta value of 12.9946 degrees (this is the angle from his initial running direction)

Answer: buoyancy forceexplanation: in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.