Agrapefruit falls from a tree and hits the ground .75 seconds later. how far did the grapefruit drop? what was its speed?

1) The grapefruit is in free fall, so it moves by uniformly accelerated motion, with constant acceleration . Calling h its height at t=0, the height at time t is given by

We are told thatn when  the grapefruit hits the ground, so h(0.75 s)=0. If we substitute these data into the equation, we can find the initial height h of the grapefruit:



2) The speed of the grapefruit at time t is given by

where  is the initial speed of the grapefruit. Substituting t=0.75 s, we find the speed when the grapefruit hits the ground:

A) acceleration. this seems to be the one that makes sense.