A0.10 kg ball of dough is thrown straight up into the air with an initial speed of 15 m/s. a. find the momentum of the ball of dough at its maximum height. b. find the momentum of the ball of dough halfway to its maximum height on the way up

(a) The momentum of ball at the maximum height is zero.

(b) The momentum of ball at halfway of maximum height is 1.06 kg-m/s.

Given data:

The mass of ball is, m = 0.10 kg.

The initial speed of ball is, u = 15 m/s.

(a)

At maximum height (h) the ball will stop, so final speed of ball is, v = 0 m/s. Then the momentum at the maximum height is,

Thus, the momentum of ball at the maximum height is zero.

(b)

Apply the third kinematic equation of motion to obtain the maximum height (h) achieved by the ball as,

For halfway height,

h' = h/2

h'=11.47/2

h'=5.74 m

Again apply third kinematic equation of motion to obtain the speed (v') at halfway height as,

Then momentum (p') is calculated as,

Thus, the momentum of ball at halfway of maximum height is 1.06 kg-m/s.

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