Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. each elevator has a mass of 1,000 kg. the second elevator takes 10 seconds to do this work. calculate the power output of the second motor.

The correct answer is 9800 Watt.

Explanation:

In the given problem, work done is equal to the potential energy.

The expression for the power output in the case of electric motor is as follows;

                                                     ....... (1)

here, m is the mass of the object, g is the acceleration due to gravity, h is the height and t is the time taken.

Calculate the power output of the second motor by using equation (1).

Put m= 1000 kg, g= 9.8 meter per second square, h= 10 m and t= 10 s.

Therefore, the power output of the second motor is 9800 Watt.

a and b sometimes have a positive value

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