How far must you stretch a spring with k = 1800 n/m to store 280 j of energy?

55.8 cm Using Hooke's law, the energy stored in a spring is E = 0.5 kx^2 where E = Energy k = spring constant x = deflection of spring So substituting the known values and solving for x, we get: E = 0.5 kx^2 280 J = 0.5 1800 N/m x^2 280 N*m = 900 N/m x^2 0.311111111 m^2 = x^2 0.557773351 m = x Rounding to 3 significant figures, gives us 55.8 cm. So the spring must be stretched 55.8 cm to store 280 Joules of energy.

B) raising the temperature and reducing the volume of the gas.|-/