Physics, 18.07.2019 09:20, rubend661

An apparatus like the one cavendish used to find g has a large lead ball that is 7.7 kg in mass and a small one that is 0.061 kg. their centers are separated by 0.05 m. find the force of attraction between them. the value of the universal gravitational constant is 6.67259 × 10−11 n · m2 /kg2 . answer in units of n.

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answered: sleepingfrosty5611

The force of attraction between them is $(1.2536).10^{-8}N$

Explanation:

We are going to use the Newton's Gravitational Law to solve this exercise.

The law states that :

The gravitational force between two objects is proportional to their masses and inversely proportional to the square of the distance between their centers.

The equation is :

$F_{G}=\frac{G.m_{1}.m_{2}}{d^{2}}$

Where '''' is the universal gravitational constant.

Where '' $m_{1}$ '' and '' $m_{2}$ '' are the masses of the objects.

Where '''' is the distance between the centers of the objects.

If we replace all the data in the equation :

$F_{G}=\frac{(6.67259).10^{-11}\frac{N.m^{2}}{kg^{2}}.(7.7kg).(0.061kg)}{(0.05m)^{2}}$

$F_{G}=(1.2536).10^{-8}N$

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