One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force fis applied to the other end of the rope as shown in the drawing. the door has a weight of 145 n and is hinged on the right. what is the maximum magnitude of ffor which the door will remain at rest?

The maximum magnitude of F for which the door will remain at rest is about 265 N

Let's recall Moment of Force as follows:

where:

τ = moment of force ( Nm )

F = magnitude of force ( N )

d = perpendicular distance between force and pivot ( m )

Let us now tackle the problem !

Given:

weight of the door = w = 145 N

direction of the force = θ = 20°

distance between hinge and the applied force = d = 2.50 m

length of the door = L = 3.13 m

Asked:

magnitude of the force = F = ?

Solution:

If the door is in equilibrium position , then :

Grade: High School

Subject: Physics

Chapter: Moment of Force

trig 15.3 cos

object 2 because all the other ones are wrong