An ideal gas is allowed to expand isothermally from 2.00 l at 5.00 atm in two steps: a. against a constant external pressure of 3.00 atm, followed by b. against a constant external pressure of 2.00 atm. calculate q and w. (101.33 j = 1 l atm)

Heat added to the gas = Q = 743 Joules

Work done on the gas = W = -743 Joules

The Ideal Gas Law that needs to be recalled is:

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Let us now tackle the problem !

Given:

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

Unknown:

Work done on the gas = W = ?

Heat added to the gas = Q = ?

Solution:

Ideal gas is allowed to expand isothermally:

Next we will calculate the work done on the gas:

Using the same method as above:

Next we will calculate the work done on the gas:

Finally we could calculate the total work done and heat added as follows:

Grade: High School

Subject: Physics

Chapter: Pressure

as a general rule, scissors have blades less than 6 in (15 cm) long and usually have handles with finger holes of the same size. shears have blades scissors used to cut hair or fabric must be much sharper.