A5 n force pushes on the right side of a box. at the same time, a 10 n force pushes on the left side of the box. what happens to the box?

The box will displace towards right side.

Explanation:

In the given problem, a 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. The net force acting on the force is 5 N.

The magnitude of the force acting on the box from the left side is more than the force acting on the box from the right side. The body will displace in that direction in which the magnitude of the applied force is more.

The box is displaced to right by a net force of 5 N.

Therefore, the box will displace towards right side.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)