Aroller coaster car travels through a loop in 3.1 s with a centripetal acceleration of 26 m/s^2. what is the radius of the roller coaster loop? a. 6.3 m b. 20 m c. 25 m

r = 6.32 meters

Explanation:

Given that,

The centripetal acceleration acting on the roller coaster,

Time taken by the car, t = 3.1 s

The centripetal acceleration act on an object when it moves in circular path. Its formula is given by :

v is the velocity of car,

On rearranging above equation,

r = 6.32 meters

So, the radius of the roller coaster loop is 6.3 meters. Hence, this is the required solution.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.