How long does a radar signal take to travel from earth to venus and back when venus is brightest?

Given data :

Velocity of radar signal, v = Velocity of light = 3 x 10^8 m/s

Greatest distance between Venus and Earth d1 = 0.47 AU = 0.47 AU (a.5 x 10^11 m / 1 AU) = 7.1x10^10 m

Closest distance between Venus and Earth, d2 = 0.28 AU = 0.28 AU (1.5 x 10^11 m / 1 AU)= 4.2 x 10^10 m

The time take by radar signal to travel from Earth to Venus and back when Venus is brightest is calculated as

T1 = 2d1/v = 2(7.a x 10^10 m / 3 x10^8 m/s) = 473 s

The time taken by radar signal to travel from Earth to Venus and back when Venus is closest is calculated as

T2 = 2d1/v = 2 (4.2 x 10^10 m) / 3 x 10^8 m/s = 280 s

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

conduct current i mean it makes sense