Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. the ceiling is of height 3.6 m, and the balloons are launched at a velocity of 11 m/s. the acceleration of gravity is 9.8 m/s 2 . at what angle must they be launched to just graze the ceiling?

angle above the horizontal.

Step by Step Solution :

Given :

Launch speed = 11 m/sec

Height of the ceiling = 3.6 m

Calculation :

Let be the launch angle, measured above the horizontal.

Vertical component of initial speed is

We know that

angle above the horizontal they launched to just graze the ceiling.

For more information, refer the link given below

link

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

the inner core.

good luck: )

klicker