An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the floor of the elevator on a(n) 76 kg passenger? answer in units of n.

The upward force exerted on the passenger is 836 N.

The given parameters;

The upward force on the object can be determined by applying Newton's second law of motion.

Since the elevator is ascending upwards, the force on the elevator will become greater and the passenger feels a heavier weight.

∑F = ma + mg

F = m(a + g)

F = 76(1.2 + 9.8)

F = 836 N.

Thus, the upward force exerted on the passenger is 836 N.

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