Adaredevil decides to jump a canyon of width 8.88 m. to do so, he drives a motorcycle up an incline sloped at an angle of 22.5 ◦ . the acceleration of gravity is 9.8 m/s 2 . what minimum speed must he have in order to clear the canyon? answer in units of m/s.

What we need first is the formula to calculate maximum horizontal distance. It is: R = v^2(Sin 2A)/g where R is range, v is velocity, A is angle, and g is the gravity constant. we know that R=8.88 meters, A= 22.5 degrees, and g= 9.8 m/s^2 What we are looking for is v=?. We need to solve the equation for v. That gives us: v =((R*g)/(Sin(2* 22.5)))**1/2 Next, all we have to do is plugin the values. v = ((8.88m * 9.8 m/s**2)/(sin(2*22.5 degrees))**1/2 All this give us v = 10.11 m/s

Pretty sure the answer is b : )

Well the magnitude of its acceleration related to that car starts with the oil change like when you have to change the oil in your car you have to make sure that your precious car is starting really propley and very well