Abattleship steams due east at 24 km/h. a submarine 4.0km away fires a torpedo that has a speed of 50 km/h. if the bearing of the ship as seen from the submarine is 20 degrees north of ( a. in what direction should the torpedo be fired to hit the ship? ( b. how long will it take the torpedo to reach the battleship?

3.75 kimThe torpedo will be fired at an angle of 46.8 degrees east of North. If you substitute the angle to the equation t = 0.075h / cosx, where x is the computed angle and h is a constant 60 min / 1 hr, then the torpedo will hit the battleship in 0.66 min.
Therefore, the answer for a) 46.8 degrees East of North and b) 0.66 minutes

D=m/v m=d*vd=densitym=massv=volumed(ether)=0.71 gr/cm³=0.71 gr/ mlv=130 mlm=d*vm=0.71 gr/ml*(130 ml)=92.3 gm=92.3 g

Answer would be