A1.60-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. you may want to review ( pages 204 - 205) . part a if you ignore the weight of the bar itself, how far from the left end of the barbell is the center of gravity

Refer to the diagram shown below.

The weight at the left end is
W₁ = (25.0 kg)*(9.8 m/s²) = 245 N
The weight at the right end is
W₂ = (37.0 kg)*(9.8 m/s²) = 362.6 N
The reaction at the fulcrum is
R = W₁ + W₂

Let x =  distance of the fulcrum (c.g.) from the left end.
For equilibrium, take moments about the center of gravity (c.g).
(245 N)*(x m) - (362.6 N)*(1.6-x m) = 0
245x - 580.16 + 362.6x = 0
607.6x = 580.16
x = 0.955 m

0.955 m

The answer is c hope this

Ithink it is c ,i hope i you