Physics, 05.07.2019 19:50, millie54

You have negotiated with the omicronians for a base on the planet omicron persei 7. the architects working with you to plan the base need to know the acceleration of a freely falling object at the surface of the planet in order to adequately design the structures. the omicronians have told you that the value is gop7=7.29 flurg/grom^2, but your architects use the units meter/second^2, and from your previous experience you know that both the omicronians and your architects are terrible at unit conversion. thus, it's up to you to do the unit conversion. fortunately, you know the unit equality relationships: 5.24 flurg=1 meter and 1 grom=0.493 second. what is the value of gop7 in the units your architects will use, in meter/second^2?

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5.72 m/s^2 First, we have available 2 conversion units. 5.24 flurg/m and 0.493 s/grom I chose the units to describe those two conversions by making the denominator equal to 1 in both cases, so there are 5.24 flurgs per meter and 0.493 seconds per grom. Now we've been given 7.29 flurg/grom^2 and we want to convert to m/s^2. So we need to figure out how to multiply or divide our conversion factors to cancel out the flurg and grom units. Let's see about cancelling the flurg unit 1st and replacing it with meters Let's try multiplication flurg/grom^2 * flurg/m = flurg^2/(m*grom^2) That won't work. So let's try division flurg/grom^2 / flurg/m = flurg/grom^2 * m/flurg = (m*flurg)/(grom^2 * flurg) The flurg on top and bottom, cancel, so = m/grom^2 So dividing by our length conversion will work correctly. Let's do it. 7.29 flurg/grom^2 / 5.24 flurg/m = 1.391221374 m/grom^2 Now we want to convert from m/grom^2 to m/(s grom) using our time conversion factor. Since we want s in the denominator and it's in the numerator, a division looks good. So m/grom^2 / s/grom = m/grom^2 * grom/s = (m*grom)/(grom^2 * s) = m/(grom * s) And it is good. So let's do it 1.391221374 m/grom^2 / 0.493 s/grom = 2.821950049 m/(grom s) We still have one more grom to get rid of. And since it's in the same place as the previous one, let's divide again. 2.821950049 m/(grom s) / 0.493 s/grom = 5.72403661 m/s^2 Since all our input is to only 3 significant figures, round the result to 3 significant figures. Giving 5.72 m/s^2

answered: kulfif8441

The value of gravitational acceleration at Omicronian in standard units is $2.80 \;\rm meter/second^{2$ .

Given data:

The value of gravitational acceleration at planet Omicron Persei 7 is,

$g__{{OP7}}} =7.29 \;\rm \;\rm flurg/grom^{2}$ .

We also know that

$1 \;\rm meter = 5.24 \;\rm flurg\\\\\1 \;\rm flurg = \dfrac{1}{5.24} \;\rm meter =0.190\;\rm meter\\\\1 \;\rm grom = 0.493 \;\rm seconds\\$ .

Since, the given value of Omicronian gravitational acceleration is in arbitrary set of units. And the standard unit for the acceleration is $m/s^{2}$ . Then converting the arbitrary units to standard units as,

$1 \;\rm flurg/grom^{2} =\dfrac{0.190 \;\rm meter}{0.493 \;\rm second^{2}}\\\\1 \;\rm flurg/grom^{2} =0.385\;\rm meter/second^{2}$

Now, converting the given value as,

$g__{{OP7}}} =7.29 \;\rm \;\rm flurg/grom^{2} \times \dfrac{0.385 \ meter/second^{2}}{1 \;\rm flurg/grom^{2}} \\\\g__{{OP7}}} =2.80 \;\rm meter/second^{2}$

Thus, we can conclude that the value of gravitational acceleration at Omicronian in standard units is $2.80 \;\rm meter/second^{2$ .

Learn more about the unit conversion from here;

link

answered: Guest

The center is basically the heart of it

answered: Guest

The best answer is (a) which is universal law is in effect at all times. it is constantly at play in everything we do and governs our lives. it is also important to note that universal law applies to not only everything on earth, but everything in the universe as well, which is another reason why it is in effect at all times.

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You have negotiated with the omicronians for a base on the planet omicron persei 7. the architects w...