Acharge of 40 µc is pushed by a force of 15 µn a distance of 1.3 mm in an electric field. what is the electric potential difference?

C. 4.9 × 10-4 V

Explanation:

ΔV = E d  

E = force/charge = 15 µN / 40 µC = 0.375 N/C

ΔV = 0.375 N/C * 0.0013 m = C. 4.9 × 10-4 V

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)